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5t^2-30t+45=0
a = 5; b = -30; c = +45;
Δ = b2-4ac
Δ = -302-4·5·45
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$t=\frac{-b}{2a}=\frac{30}{10}=3$
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